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Hello,I cannot figure out what theta is.I have tried almost everything & my open math still says that my answers are wrong. Can anyone help?

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  • 2 months ago
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    r = √(3² + (-10²)

    r = 10.44030650891055

    r ≈ 10.440 <–––––

    ----------------

    3 - 10i therefor

    ϴ is in the IV Quadrant

    Reference angle

    Tan ϴ = -10/3

    ϴ = arctan (-10/3)

    ϴ = -1.27933953231703

    ϴ = 2π + -1.27933953231703

    ϴ = 5.003845774862557

    ϴ = 5.004 <–––––

    • Savannah2 months agoReport

      Thank you sooooo much Michael! My open math said those answers are correct. Thank you for helping!

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  • Anonymous
    2 months ago

    No I can't help.

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