Does size of positive electrode also determine the capacitance of a cap or only the negative electrode (which accumulated electrons)?
- skeptikLv 71 month agoFavorite Answer
The area in the formula for capacitance of parallel plates is that of the *overlap* between the two. Any part of either plate that lies outside this overlap zone is ignored in the calculation.
- ️️️️️️️️️️️️️️️Lv 71 month ago
not at all in my opinion
- PhilomelLv 71 month ago
The capacitance of a capacitor is a function of the total area of both electrodes, the space or medium between them and the dielectric constant of that space or medium, not just one but both plates.
- Thomas CLv 61 month ago
The size of both capacitor plates affects the capacitance value.
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- silver dLv 71 month ago
Capacitance is directly proportional to the area of overlap of the two plates, regardless of polarity. Making one plate larger without increasing the amount of overlap does nothing to the capacity.
- LGLv 71 month ago
Both electrodes accumulate charge. The more charge that can be pushed onto the plates at a given voltage, the greater the capacitance. It's the proximity of the opposite charge that allows more charge to be pushed onto each plate. If there was no opposite plate, the electric repulsion of all the like charges would prevent any further charge from accumulating. The closer we bring the opposite plate, the greater the attraction of the electric field from that plate, counteracting the repulsion of all the like charges on this plate, and the more charge can accumulate on this plate. So lots of plate area with close proximity to the opposite plate is what gives great capacitance.
- 異域秦後人Lv 71 month ago
The smaller one in size determines the capacitance.
- 1 month ago
The basic equation for capacitance of a parallel plate capacitor is capacitance= epsilon * area/ distance The area of both plates is in the numerator. For other designs, the actual equations are a little different.
- Jim MoorLv 71 month ago
The surface area matters, so yes